Question

A student places a block of hot metal into a coffee cup calorimeter containing75.0 g of water. the water temperature rises from 23.7 °c to 32.1 °c. how much heat did the water absorb?

Answer 1

The water absorbed approximately 2637.36 Joules of heat.

Step-by-step explanation:

To calculate the amount of heat absorbed by the water, we can use the formula:

q = m * C * ΔT

where q is the heat absorbed, m is the mass of the water, C is the specific heat capacity of water, and ΔT is the change in temperature.

Given that the water mass is 75.0 g, the specific heat capacity of water is 4.184 J/g°C, and the temperature change is ΔT = 32.1 °C - 23.7 °C = 8.4 °C, we can substitute these values into the formula:

q = (75.0 g) * (4.184 J/g°C) * (8.4 °C) = 2637.36 J

Therefore, the water absorbed approximately 2637.36 Joules of heat.