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A container of gas is initially at 0.500 atm and 25 ˚c. what will the pressure be at 125 ˚c?

User Buglinjo
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1 Answer

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Final answer:

To determine the final pressure of the gas in a container initially at 0.500 atm and 25 ˚C, we can use the combined gas law equation. The final pressure will be approximately 0.664 atm at 125 ˚C.

Step-by-step explanation:

To determine the final pressure of the gas, we can use the combined gas law equation:

P1V1/T1 = P2V2/T2

Where P1 and T1 are the initial pressure and temperature, and P2 and T2 are the final pressure and temperature.

Plugging in the given values:

P1 = 0.500 atm, T1 = 25 ˚C = 298 K

P2 = ?, T2 = 125 ˚C = 398 K

V1 and V2 are not given, so we can assume they remain constant.

Using the equation, we can solve for P2:

P2 = (P1 * T2) / T1 = (0.500 atm * 398 K) / 298 K = 0.664 atm

Therefore, the pressure will be approximately 0.664 atm at 125 ˚C.

User Dels
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