Question

A tennis ball is thrown upwards from the edge of a cliff with a speed of 10m/s​. It lands on the ground below the cliff 3.0 seconds later. Disregarding air resistance and using a coordinate system where upward is positive, what is the displacement of the tennis ball? Provide the answer in meters, rounded to two significant digits.

Answer 1

The displacement of the tennis ball thrown upwards from the edge of a cliff can be calculated by finding the height it reaches and subtracting the initial height. Using the equation h = (1/2)gt^2, the displacement is approximately 44.1 meters.

Step-by-step explanation:

Using the equations of motion, we can determine the displacement of the tennis ball by finding the height it reaches and subtracting the initial height. The formula to calculate the height reached by an object in free fall is:

h = (1/2)gt^2

where h is the height, g is the acceleration due to gravity (9.8 m/s^2), and t is the time.

In this case, the initial height is 0 because the ball starts at the edge of the cliff. Substituting the given values, we have:

h = (1/2)(9.8 m/s^2)(3.0 s)^2

Simplifying the equation gives:

h = 44.1 m

Therefore, the displacement of the tennis ball is approximately 44.1 meters.