15.3k views
5 votes
A solid has a volume of 8 cm³. when weighed on a spring scale calibrated in grams, the scale indicates 20 g. what does the scale indicate if the object is weighed while immersed in a liquid of density 2 g/cm³?

A) -136.8 g
B) -116.8 g
C) 20 g
D) 156.8 g
E) 176.8 g

User Tirno
by
7.2k points

1 Answer

6 votes

Final answer:

The scale will still indicate 20 g when the object is weighed while immersed in the liquid of density 2 g/cm³.

This correct answer is C)

Step-by-step explanation:

To find the reading on the scale when the object is weighed while immersed in a liquid of density 2 g/cm³, we can use the formula Density = Mass/Volume. We know that the volume of the object is 8 cm³. From the given information, the mass of the object is 20 g. So, we can calculate the density of the object as follows:



Density = Mass/Volume = 20 g/8 cm³ = 2.5 g/cm³



Now that we have the density of the object, we can use the formula Density = Mass/Volume to find the mass when the object is immersed in the liquid of density 2 g/cm³:



2.5 g/cm³ = Mass/8 cm³



Mass = 2.5 g/cm³ * 8 cm³ = 20 g



Therefore, the scale will still indicate 20 g when the object is weighed while immersed in the liquid of density 2 g/cm³. So, the correct option is C) 20 g.

This correct answer is C)

User Abhijith Madhav
by
8.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.