Question

A speedy rabbit is hopping to the right with a velocity of 4ms⁻¹ when it sees a carrot in the distance. The rabbit speeds up its maximum velocity of 13ms⁻¹ with a constant acceleration of 2ms⁻² rightward. How many seconds does it take the rabbit to speed up from 4ms⁻¹ to 13ms⁻¹?

Answer 1

It takes the rabbit 4.5 seconds to accelerate from 4 m/s to 13 m/s with a constant acceleration of 2 m/s².

Step-by-step explanation:

To calculate the time it takes for the rabbit to speed up from 4 m/s to 13 m/s with a constant acceleration, we can use the formula for acceleration: a = (v - u) / t, where a is the acceleration, v is the final velocity, u is the initial velocity, and t is the time.

Here, the given values are:
Initial velocity, u = 4 m/s
Final velocity, v = 13 m/s
Acceleration, a = 2 m/s²

Rearranging the formula to solve for t gives us: t = (v - u) / a.

Substituting the known values, we get:
t = (13 m/s - 4 m/s) / 2 m/s²
t = 9 m/s / 2 m/s²
t = 4.5 seconds

It takes the rabbit 4.5 seconds to reach its maximum velocity of 13 m/s from a velocity of 4 m/s with a constant acceleration of 2 m/s² rightward.