Question

A rectangular block of wood, 10.0 cm x 15.0 cm x 46.5 cm, has a specific gravity of 0.610. Determine the buoyant force that acts on the block when it is placed in a pool of fresh water with a density of 1.00 x 10³ kg/m³

Answer 1

The buoyant force acting on the wooden block is approximately 68.4 N.

Step-by-step explanation:

To determine the buoyant force acting on the wooden block, we need to calculate its volume and then use the formula for buoyant force. The formula for calculating buoyant force is given by Fb = ρVg, where Fb is the buoyant force, ρ is the density of the fluid, V is the volume of the object submerged in the fluid, and g is the acceleration due to gravity.

First, let's calculate the volume of the wooden block: V = lwh = (10.0 cm)(15.0 cm)(46.5 cm) = 6975 cm³ = 0.006975 m³.

Now we can calculate the buoyant force: Fb = (density of water) * V * g = (1000 kg/m³) * (0.006975 m³) * (9.8 m/s²) = 68.3815 N. Therefore, the buoyant force acting on the wooden block is approximately 68.4 N.