Final answer:
To avoid crashing into the sea, the pilot must start pulling his plane out of the dive at an altitude of approximately 464 meters.
Step-by-step explanation:
To answer this question, we need to determine the altitude at which the pilot must begin to pull his plane out of the dive. We know that the pilot can withstand an acceleration of 8.0 g's without blacking out, and his diving speed is 270 m/s.
First, we need to convert the speed to km/h: 270 m/s * 3.6 km/h = 972 km/h.
Next, we need to calculate the altitude. We can use the formula: v² = u² + 2as, where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the distance.
At the highest point of the dive, the final velocity should be 0 km/h, the initial velocity is 972 km/h, and the acceleration is -8 * 9.8 m/s² (negative because it's an upward acceleration). Solving for s, we get the distance of 464.34 meters.
Therefore, the pilot must start pulling his plane out of the dive at an altitude of approximately 464 meters. So, the correct answer is option C) 464 m.