Question

A series silicon diode circuit has a 2 kω resistor and a 10 v source. determine vdq if idq is 4.5 ma.

a) 1 v
b) 0.7 v
c) 2 v
d) 11.5 v

Answer 1

The voltage drop across the silicon diode (Vdq) in the circuit with a 2 kΩ resistor and a 10 V source, given the current (Idq) is 4.5 mA, is calculated using Ohm's Law and is found to be 1 V. Option (a) 1 V is the correct answer.

Step-by-step explanation:

The student's question involves calculating the voltage drop across a diode when there is a known current flowing through the circuit. In this case, the silicon diode is in series with a 2 kΩ resistor and a 10 V source. The given current through the diode (Idq) is 4.5 mA (milliamps).

Using Ohm's Law, which states that voltage (V) is equal to current (I) times resistance (R), we can calculate the voltage drop across the resistor. The formula is:

Voltage drop (Vr) = Idq × Resistance

First, let's calculate the voltage drop across the resistor:

Vr = 4.5 mA × 2 kΩ

Vr = 0.0045 A × 2000 Ω

Vr = 9 V

Now, to find the voltage drop across the diode (Vdq), we use the total voltage supplied by the source (Vs) and subtract the voltage drop across the resistor (Vr).

Vdq = Vs - Vr

Vdq = 10 V - 9 V

Vdq = 1 V

Therefore, the correct answer for the voltage drop across the diode when the current is 4.5 mA is 1 V, which corresponds to option (a) 1 V.