Final answer:
The motorcycle's average velocity during acceleration is 7.5 m/s, and it traveled a total distance of 210.4672 m during the 56 seconds of acceleration period.
The correct answer is none of all.
Step-by-step explanation:
To find the average velocity of a motorcycle accelerating from rest, we use the formula for average velocity, which, when starting from rest, is simply the final velocity divided by 2. In this case, the final velocity (v) is 15 m/s and the initial velocity (u) is 0 m/s (since it starts from rest), so the average velocity (vavg) is:
vavg = (u + v) / 2
vavg = (0 + 15) / 2
vavg = 15 / 2
vavg = 7.5 m/s
To calculate the distance traveled, we use the formula for distance with constant acceleration, which is:
d = u * t + 0.5 * a * t2
Since u is 0 (starts from rest), the formula simplifies to:
d = 0.5 * a * t2
We already have t (56 s), but we need to find acceleration (a) using the formula:
a = (v - u) / t
a = (15 - 0) / 56
a = 15 / 56
a = 0.2679 m/s2
Now, we can find the distance (d):
d = 0.5 * 0.2679 * 56 * 56
d = 0.5 * 0.2679 * 3136
d = 420.9344 m2/s2
d = 210.4672 m
So, the motorcycle's average velocity was 7.5 m/s and it traveled a distance of 210.4672 m.