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Solve using a punnett square. one parent has brown hair (bb) and the other parent has blonde hair (bb). if they have four children, what will the probability be that they will have a child with blonde (bb) hair?

User Drizin
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Final answer:

When both parents have the genotype 'bb' for hair color, all their children will have 100% probability of also having blonde hair (bb), as demonstrated by the Punnett square showing only 'bb' results in every box.

Step-by-step explanation:

To solve using a Punnett square, we must determine the probability that the parents with brown hair (bb) and blonde hair (bb) will have a child with blonde hair (bb). Both parents can only pass on a 'b' allele since they are homozygous recessive for the hair color gene.

Here's how you set up the Punnett square:

  • Parent 1: bb (two 'b' alleles)
  • Parent 2: bb (two 'b' alleles)

When you cross these alleles, all the possible combinations in the Punnett square's four boxes will be 'bb', as each parent can only contribute a 'b' allele.

Therefore, 100% (or all four children) will have blonde hair (bb), as this is the only possible combination of alleles from these two parents.