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Find the volume of the solid that results when the region bounded by y=sqrt(169-x^2) and y=12 is revolved about the x-axis.

User ErnieL
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Final answer:

To find the volume of the solid formed by revolving the given region about the x-axis, you can use the method of cylindrical shells.

Step-by-step explanation:

To find the volume of the solid formed by revolving the region bounded by y = sqrt(169 - x^2) and y = 12 about the x-axis, we can use the method of cylindrical shells.

The volume of the solid can be calculated by integrating the circumference of each cylindrical shell multiplied by its height.

The integral setup will be: V = 2π ∫[from -12 to 12] x (12 - sqrt(169 - x^2)) dx.