Final answer:
In a proof by contrapositive of the given theorem, option a assumes that either x and y are both odd, and proves that x + y is even or x and y are both even.
Step-by-step explanation:
The theorem states that if the sum of two integers, x and y, is even, then x and y have the same parity (i.e., they are both even or both odd). In a proof by contrapositive, we assume the negation of the conclusion and prove the negation of the hypothesis. Let's analyze each option:
a. Assumed: either x and y are both odd. Proven: x + y is even or x and y are both even.
b. Assumed: either x is odd. Proven: x + y is even.
c. Assumed: either x and y are both even or x is even and y is odd. Proven: x + y is odd.
d. Assumed: either x is odd and y is even or x is even and y is odd. Proven: x + y is odd.
Therefore, the correct answer is a. The assumptions and proven facts in a proof by contrapositive are logically equivalent to those in the original theorem.