Question

Calculate the average rate of reaction between 20.0s and 10.0s given the following data. Assume A B Time(s) 0.0 5.0 10.0 15.0 20.0 O 5.0 x 10'3 M/s O 10 x 10¹ M/s O 1.2 x 10¹2 O 6.9 x 10¹9 M/s Concentration (M) of A .20 .10 .071 0.51 pts .050

Answer 1

To calculate the average rate of reaction from 20.0s to 10.0s, subtract the concentration of A at 10.0s from its concentration at 20.0s and divide by the time elapsed. The average rate for this interval is 0.0021 M/s.

Step-by-step explanation:

The question concerns the calculation of the average rate of reaction between two different time points. To find the average rate between 20.0s and 10.0s, we need to use the change in concentration of substance A over this time period. According to the provided data, at 20.0s the concentration of A is 0.050 M and at 10.0s it is 0.071 M.

The formula to calculate the average rate of reaction (A → B) is:

Rate = Δ[A]/Δt = ([A] at 10.0s - [A] at 20.0s) / (20.0s - 10.0s)

Plugging in the values, we get:

Rate = (0.071 M - 0.050 M) / (20.0s - 10.0s) = 0.021 M / 10.0s = 0.0021 M/s

Therefore, the average rate of reaction between 20.0s and 10.0s is 0.0021 M/s.