Final answer:
The weight of an iceberg with a volume of 7690 cubic feet is approximately 181.7 tons.
Step-by-step explanation:
Icebergs displace a significant volume of water, and their weight is crucial for understanding their impact on buoyancy and stability. To calculate the weight of an iceberg, one must consider the density of ice, which is approximately 0.92 grams per cubic centimeter or 57.5 pounds per cubic foot. Given the iceberg's volume of 7690 cubic feet, the weight can be calculated by multiplying the volume by the density of ice.
Therefore, 7690 cubic feet * 57.5 pounds/cubic foot = 441,175 pounds. To convert this weight into tons, divide by 2000 pounds per ton, yielding approximately 220.6 tons. However, this doesn't account for the portion of the iceberg submerged in water, which is around 10% of its total mass. Adjusting for buoyancy, the weight of the iceberg becomes approximately 181.7 tons.