Question

a charge of -3.3 × 10-9 c is at the origin and a charge of 9.7 × 10-9 c is on the x-axis at x = 3 m. at what two locations on the x-axis (xpositive, xnegative) is the potential zero?

Answer 1

To find the locations on the x-axis where the potential is zero, use the formula for the electric potential due to a point charge and set it to zero. The potential is zero at x = -1.14 m and x = 1.71 m.

Step-by-step explanation:

To find the locations on the x-axis where the potential is zero, we can use the formula for the electric potential due to a point charge: V = k*q/r, where V is the potential, k is the electrostatic constant (9 x 10^9 Nm^2/C^2), q is the charge, and r is the distance from the charge. Since we have two charges, we need to find the potential at each location and set it to zero. Setting up the equation for the charge at the origin, we get: 0 = k*(-3.3 x 10^-9)/x - k*(9.7 x 10^-9)/(x-3). Solving for x, we find that the potential is zero at x = -1.14 m and x = 1.71 m.