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Sample 8 of Problem 4-3 was analyzed seven times, with x= 1.527 93 and s = 0.000 07. Find the 99% confidence interval for sample 8

User Zhianc
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Final answer:

To find the 99% confidence interval for sample 8, you need to calculate the margin of error using the formula ME = z * (s / sqrt(n)), where z is the z-value for the confidence level, s is the standard deviation of the sample, and n is the sample size. Then, subtract and add the margin of error from the sample mean to get the confidence interval.

Step-by-step explanation:

To find the 99% confidence interval for sample 8, we first need to calculate the margin of error (ME). The margin of error is given by the formula: ME = z * (s / sqrt(n)), where z is the z-value corresponding to the confidence level, s is the standard deviation of the sample, and n is the sample size. In this case, we are given x = 1.52793 and s = 0.00007. We need to find the z-value for a 99% confidence level. The z-value can be found using a standard normal distribution table or a z-table calculator. Let's assume that the z-value for a 99% confidence level is 2.576. The sample size, n, is 7 in this case. Now we can substitute the values into the formula to calculate the margin of error:

ME = 2.576 * (0.00007 / sqrt(7)) = 0.000061862.

Next, we can calculate the confidence interval by subtracting and adding the margin of error from the sample mean:
x - ME = 1.52793 - 0.000061862 = 1.527868138
x + ME = 1.52793 + 0.000061862 = 1.527991862

Therefore, the 99% confidence interval for sample 8 is (1.527868138, 1.527991862).

User Mpdc
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