Question

A remote-controlled car is moving in a vacant parking lot. The velocity of the car as a function of time is given by

v =[5.00 m/s−(0.0180 m/s^3)t^2]i^ + [2.00 m/s+(0.550 m/s^2)t]j^
​What is the magnitude of the velocity of the car at t=5.50 s ?

Answer 1

To find the magnitude of the velocity of the car at t=5.50 s, substitute t=5.50 s in the given velocity function v(t) and solve for v(5.50 s).

Step-by-step explanation:

To find the magnitude of the velocity of the car at t=5.50 s, we need to substitute the value of t in the given velocity function v(t).

First, substitute t=5.50 s:

v(5.50 s) = [5.00 m/s - (0.0180 m/s^3)(5.50 s)^2]i^ + [2.00 m/s + (0.550 m/s^2)(5.50 s)]j^

Solve for v(5.50 s) to find the magnitude of the velocity of the car at t=5.50 s.