35.7k views
2 votes
Given the vectors a =< 4,2 > and b = -2,-2 >, find an exact expression for the angle between the two vectors. Then find the angle between the two vectors, in degrees rounded to the nearest degree.

1 Answer

4 votes

Final answer:

To find the angle between vectors a and b, we can use the dot product formula and the magnitude of the vectors. The dot product of two vectors a and b is given by the expression a · b = |a| * |b| * cos(theta), where theta is the angle between the vectors.

Step-by-step explanation:

To find the angle between the vectors a and b, we can use the dot product formula and the magnitude of the vectors. The dot product of two vectors a and b is given by the expression a · b = |a| * |b| * cos(theta), where theta is the angle between the vectors. Rearranging the formula, we have cos(theta) = (a · b) / (|a| * |b|). From the given vectors, a = <4, 2> and b = <-2, -2>. The dot product of a and b is (4 * -2) + (2 * -2) = -14. The magnitude of vector a is |a| = sqrt((4^2) + (2^2)) = sqrt(20) = 2sqrt(5), and the magnitude of vector b is |b| = sqrt((-2)^2 + (-2)^2) = sqrt(8) = 2sqrt(2).

Substituting these values into the formula, we have cos(theta) = (-14) / (2sqrt(5) * 2sqrt(2)). Simplifying, we get cos(theta) = -14 / (4sqrt(10)) = -7 / (2sqrt(10)). To find the angle theta, we can take the inverse cosine of cos(theta). Finally, we can convert the angle from radians to degrees by multiplying by 180 and dividing by pi.

User Thirdender
by
8.0k points