Question

A driver in a car goes around a curve in the road. The radius of curvature for the road is 50.0 meters. The speed of the car is 24.6 m/s. What is the direction and magnitude of the centripetal acceleration on the driver during the turn?

A) Magnitude: 12.3 m/s², Direction: Radially inward
B) Magnitude: 1.23 m/s², Direction: Tangentially outward
C) Magnitude: 12.3 m/s², Direction: Tangentially outward
D) Magnitude: 1.23 m/s², Direction: Radially inward

Answer 1

The magnitude of the centripetal acceleration on the driver during the turn is approximately 6.0588 m/s², radially inward.

Step-by-step explanation:

The centripetal acceleration of the car can be found using the formula:

Centripetal acceleration = (velocity2) / radius

Given that the radius of curvature is 50.0 meters and the speed of the car is 24.6 m/s, we can substitute these values into the formula:

Centripetal acceleration = (24.62) / 50.0 = 6.0588 m/s2

Therefore, the magnitude of the centripetal acceleration on the driver during the turn is approximately 6.0588 m/s2. The direction of the centripetal acceleration is radially inward, which means it points towards the center of the curve.