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Which of the ordered pairs is a solution to the system of inequalities:

y<2x
3x+y>4

A:(-2,2)
B:(0,2)
C:(2,2)
D(0,4)

User Andrine
by
7.9k points

1 Answer

3 votes

Final answer:

The solution for the question from the given option is option C. To determine which of the ordered pairs is a solution to the system of inequalities, we need to substitute the values of x and y into both inequalities and check if the inequalities are satisfied.

Step-by-step explanation:

To determine which of the ordered pairs is a solution to the system of inequalities, we need to substitute the values of x and y into both inequalities and check if the inequalities are satisfied.

  1. For the first inequality y < 2x, let's check each ordered pair:
    • For A: (-2,2)
      2 < 2*(-2) -> 2 < -4
      This is not true, so A is not a solution.
    • For B: (0,2)
      2 < 2*0 -> 2 < 0
      This is not true, so B is not a solution.
    • For C: (2,2)
      2 < 2*2 -> 2 < 4
      This is true, so C is a solution.
    • For D: (0,4)
      4 < 2*0 -> 4 < 0
      This is not true, so D is not a solution.
  2. For the second inequality 3x + y > 4, let's check each ordered pair:
    • For A: (-2,2)
      3*(-2) + 2 > 4 -> -6 + 2 > 4
      This is not true, so A is not a solution.
    • For B: (0,2)
      3*0 + 2 > 4 -> 2 > 4
      This is not true, so B is not a solution.
    • For C: (2,2)
      3*2 + 2 > 4 -> 6 + 2 > 4
      This is true, so C is a solution.
    • For D: (0,4)
      3*0 + 4 > 4 -> 4 > 4
      This is not true, so D is not a solution.

Based on our calculations, the ordered pair (2,2) is the only one that satisfies both inequalities, making it the solution to the system.

User TheJosh
by
7.4k points