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let the events a and b have p[a]=x, p[b]=y, and p[ ∪ ]=z, find p[ ∩ ], p[ ∩ ], p[ ∪ ], p[ ∪ ], p[a∩ ]

User Allejo
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Final answer:

To find the probability of events A and B occurring together (P(A ∩ B)), use the formula P(A ∩ B) = P(A) + P(B) - P(A ∪ B), substituting P(A) = x, P(B) = y, and P(A ∪ B) = z, which yields P(A ∩ B) = z - x - y. Independence or mutual exclusivity of events A and B can be determined based on the value of P(A ∩ B).

Step-by-step explanation:

Probability of Combined Events

The probability of events A and B occurring together, denoted as P(A ∩ B), can be found using the formula for the probability of the union of two events:

P(A ∩ B) = P(A) + P(B) - P(A ∪ B)

Given that P(A) = x, P(B) = y, and P(A ∪ B) = z, we can calculate P(A ∩ B) by rearranging the formula:

P(A ∩ B) = z - x - y

To determine if events A and B are independent or mutually exclusive, we look at the calculated probability of their intersection. If P(A ∩ B) equals the product of P(A) and P(B), the events are independent. However, if P(A ∩ B) is zero, the events are mutually exclusive.

User KeyKi
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