Final answer:
A) 262.5 mL. By applying Boyle's Law, a gas with an initial volume of 525 mL at 1.00 atm will have a new volume of 262.5 mL when the pressure is doubled.
Step-by-step explanation:
To solve this problem, we can use Boyle's Law which states that the volume of a gas is inversely proportional to its pressure when the temperature is constant. According to the question, the initial volume of the gas is 525 mL and the initial pressure is 1.00 atm. When the pressure is doubled, the new pressure becomes 2.00 atm. To find the new volume, we can set up the equation:
V1 x P1 = V2 x P2
where V1 is the initial volume, P1 is the initial pressure, V2 is the new volume, and P2 is the new pressure. Plugging in the values:
(525 mL) x (1.00 atm) = V2 x (2.00 atm)
Solving for V2, we get:
V2 = (525 mL x 1.00 atm) / 2.00 atm = 262.5 mL
Therefore, the new volume of the gas when the pressure is doubled is 262.5 mL.
The question you have asked relates to the behavior of gases and their volume changes in response to pressure changes, according to Boyle's Law in Chemistry. Boyle's Law states that the volume of a given mass of a gas is inversely proportional to its pressure, provided the temperature remains constant. When the pressure on a gas sample is doubled, the volume is halved, assuming no temperature change.
Given this, when the pressure of a gas that initially occupies a volume of 525 mL at a pressure of 1.00 atm is doubled to 2.00 atm, the volume will be halved. Therefore, the new volume of the gas is 262.5 mL.
Hence, the correct answer to the student's question is: A) 262.5 mL.