Final answer:
The probability that one of the five visible numbers is a 3 when rolling a fair six-sided die is 5/6, since the die has an equal chance of landing on any number, making only one scenario where '3' is not visible.
Step-by-step explanation:
The probability question we're discussing is: What is the probability that one of the five visible numbers is a 3 when a fair six-sided die is rolled and five numbers can be seen? When you roll a six-sided die, the sample space (all possible outcomes) is {1, 2, 3, 4, 5, 6}. The probability of any specific number showing, such as a 3, is 1/6 since there is one '3' and six possible outcomes.
However, if you can see five out of six sides after rolling, and you need to calculate the probability that one of these five numbers is a 3, the probability changes. Since we can see five sides, the only scenario where you won't see a '3' is when '3' is on the bottom. As the die is fair, there’s an equal chance for each number to be on the bottom. Thus, the probability that '3' is not on the bottom (and thus seen) is 5 out of 6 possible outcomes, or 5/6.