Final answer:
To calculate the mass of carbon tetrafluoride produced, we determined that 4 moles of fluorine can produce 2 moles of CF₄ based on the stoichiometry of the reaction. By multiplying the number of moles of CF₄ by its molar mass, we find that 176.02 grams of CF₄ are produced.
Step-by-step explanation:
The question asks how many grams of carbon tetrafluoride, CF₄, can be produced from the complete reaction of 4.0 moles of fluorine, F₂. To solve this, we use the balanced chemical equation C + 2F₂ → CF₄. We note that the equation implies a 1:2 molar ratio between carbon and fluorine, meaning 2 moles of fluorine (F₂) are needed to react with 1 mole of carbon to produce 1 mole of CF₄.
Since we have 4.0 moles of F₂, we can produce 2.0 moles of CF₄ (because 4.0 moles of F₂ / 2 = 2.0 moles of F₂ required per mole of CF₄). The molar mass of CF₄ (carbon tetrafluoride) is calculated by adding the atomic masses of 1 carbon (12.01 g/mol) and 4 fluorines (4 x 19.00 g/mol), giving us a molar mass of 88.01 g/mol for CF₄. Finally, to find the mass of CF₄ produced, we multiply the number of moles of CF₄ (2.0 moles) by its molar mass (88.01 g/mol):
2.0 moles CF₄ x 88.01 g/mol = 176.02 grams of CF₄.