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Find three consecutive positive odd integers such that four times the first decrease by the second is 12 more than the third.

User Rbrayb
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Final answer:

To find three consecutive positive odd integers, assume the first odd integer as x, and the subsequent odd integers will be x + 2 and x + 4. Using the given equation, solve for x by simplifying it. The resulting values will be the consecutive odd integers.

Step-by-step explanation:

To find three consecutive positive odd integers, let's assume the first odd integer as x.

The second odd integer would be x + 2, since it is consecutive.

The third odd integer would be x + 4, again because it is consecutive.

According to the given information, the equation would be: 4x - (x + 2) = (x + 4) + 12.

Simplifying the equation, we get 3x - 2 = x + 16.

Bringing the x terms to one side and the constants to the other side, we get 3x - x = 16 + 2.

Simplifying further, we get 2x = 18.

Divide both sides by 2 to solve for x, giving us x = 9.

Therefore, the three consecutive odd integers are 9, 11, and 13.

User Monduiz
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