Final answer:
The point equidistant from the points (-6,0)(-3,1)(0,0) is (-3, 1/3).
Step-by-step explanation:
The point equidistant from the points (-6,0)(-3,1)(0,0) can be found by finding the average of the x-coordinates and the average of the y-coordinates of the given points. The average of the x-coordinates is (-6 + (-3) + 0)/3 = -3 and the average of the y-coordinates is (0 + 1 + 0)/3 = 1/3. Therefore, the point equidistant from the given points is (-3, 1/3).