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write computepowers()'s base case to return 1 if val is equal to 0. ex: if the input is 4, then the output is:__________

User Katch
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Final answer:

The base case for the computepowers() function is to return 1 if the val is equal to 0.

The base case for a function named computePowers() would be written such that it returns 1 if the parameter 'val' is equal to 0.

Step-by-step explanation:

The base case for the computepowers() function is to return 1 if the val is equal to 0.

For example, if the input is 4, the function should continue recursive calls until it reaches the base case when val becomes 0, and then it will return 1.

Here is an implementation of the base case:

def computepowers(val):
if val == 0:
return 1

The base case for a function named computePowers() would be written such that it returns 1 if the parameter 'val' is equal to 0. This base case is a fundamental part of a recursive function, preventing further recursive calls when a certain condition (val == 0) is met.

The question asks to write the base case for a function computePowers() that returns 1 if the input value (val) is equal to 0. This is likely a part of a recursive function used to compute powers of a number. In programming, especially in recursive functions, a base case is a scenario in which the function can return a result without needing to make further recursive calls.

The base case for computePowers() would be written in a programming language like Python as follows:

def computePowers(val):
if val == 0:
return 1
# Additional recursive logic would go here

If the input is 4, the output would not be returned by this base case since the base case only returns 1 when val is equal to 0.

User Will Hancock
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