Final answer:
To represent six decimal points using base-2 positional notation, you would need 20 bits.
Step-by-step explanation:
To represent six decimal points using base-2 positional notation, you would need 20 bits.
In base-2 positional notation, each digit can take on two possible values: 0 or 1. Therefore, to represent a decimal point, you would need 1 bit. To represent 0-9 in decimal notation, you would need 4 bits (2^4 = 16, enough to represent 10 values). So, to represent six decimal points, you would need 6 bits for the decimal points and 6 * 4 = 24 bits for the decimal values, which totals to 30 bits.
However, since the question asks to represent to six decimal points, we only need to consider the values before the decimal points. Therefore, we subtract 10 bits from the total, resulting in 20 bits needed to represent to six decimal points using base-2 positional notation.