Final answer:
The Miller Indices for the given plane with intercepts (4, 0, 3) are (403).
Step-by-step explanation:
The Miller Indices for a plane can be determined using the formula:
(h, k, l) = (1/a, 1/b, 1/c)
where a, b, and c are the intercepts of the plane with the x, y, and z axes respectively.
From the given intercepts, we can see that the plane has intercepts of 4, 0, and 3 with the x, y, and z axes respectively. Therefore, the Miller Indices for this plane are (403).