Question

Determine the structures of compounds E through I in the following reaction scheme: 1. NaNH2 E H20 F CH;OH G NaOH Br2 NAOH I -> TFOH, CF;CH,OH 2. Br H

Answer 1

In the given reaction scheme, the structures of compounds E through I can be determined by breaking down the reactants and applying the reaction conditions and reagents. The structures are: E: TFOH, F: CH₃OH, G: NaBr + NaBrO₃, H: NaBrO₂ + NaBr + H₂O, and I: Br₂.

Step-by-step explanation:

In the given reaction scheme, the structures of compounds E through I can be determined by analyzing the reactants and products. Let's go step by step:

1. Step 1: Identify the bonds broken and formed in the reaction:

• Bonds broken: H-H bond and Br-Br bond

Step 2: Apply the reaction conditions and reagents to each compound:

• E: NaNH₂ + H₂O -> TFOH (Tetrafluoroethene)
• F: CH₃OH + H₂ -> CH₃OH (Methanol)
• G: NaOH + Br₂ -> NaBr + NaBrO₃
• H: NaOH + NaBrO₃ -> NaBrO₂ + NaBr + H₂O
• I: Br₂ -> Br₂ (Bromine)

Step 3: Write the structural formulas for the compounds:

• E: TFOH (Tetrafluoroethene)
• F: CH₃OH (Methanol)
• G: NaBr + NaBrO₃
• H: NaBrO₂ + NaBr + H₂O
• I: Br₂ (Bromine)

Therefore, the structures of compounds E through I in the reaction scheme are:

- E: TFOH (Tetrafluoroethene)

- F: CH₃OH (Methanol)

- G: NaBr + NaBrO₃

- H: NaBrO₂ + NaBr + H₂O

- I: Br₂ (Bromine)