Question

A ball is thrown straight up at time T=0 with an initial speed of 19 m/s. take the point of release to be y0= 0 and upwards to be the positive direction.

A) calculate the displacement at the time of 0.50s
B) calculate the velocity at the time 0.50s

Answer 1

The displacement at a time of 0.50s is 8.275 m, and the velocity at a time of 0.50s is 14.1 m/s.

Step-by-step explanation:

For a ball thrown straight up with an initial velocity of 19.0 m/s, we can calculate the displacement and velocity at a time of 0.50s as follows:

a) Displacement:

The displacement at a time of 0.50s can be calculated using the equation:

displacement = initial velocity * time + (1/2) * acceleration * time^2

Since the ball is thrown straight up, the acceleration is equal to -9.8 m/s^2 (negative since it's in the opposite direction of the initial velocity). Therefore, the displacement can be calculated as:

displacement = 19.0 m/s * 0.50s + (1/2) * (-9.8 m/s^2) * (0.50s)^2

displacement = 9.5 m - 1.225 m

displacement = 8.275 m

So, the displacement at a time of 0.50s is 8.275 m.

b) Velocity:

The velocity at a time of 0.50s can be calculated using the equation:

velocity = initial velocity + acceleration * time

Using the given values, the velocity can be calculated as:

velocity = 19.0 m/s + (-9.8 m/s^2) * 0.50s

velocity = 19.0 m/s - 4.9 m/s

velocity = 14.1 m/s

So, the velocity at a time of 0.50s is 14.1 m/s.