Final answer:
Two static 1-hazards exist in the given circuit: one when input A transitions from 0 to 1 and another when input B transitions from 0 to 1. Both hazards occur due to delayed output transitions.
Step-by-step explanation:
In the given circuit, there are two static 1-hazards:
- Static 1-hazard 1:
- Condition: When input A transitions from 0 to 1 while input C is already at 0.
- Timing diagram:
- Static 1-hazard 2:
- Condition: When input B transitions from 0 to 1 while input A is already at 1 and input C is already at 0.
- Timing diagram:
In both cases, the hazards occur due to the delayed transition of outputs. The timing diagrams show that there is a delay in the output transitions when hazards occur.