Question

A cylinder with a moveable piston contains 92g of nitrogen. the external pressure is constant at 1.00 atm. the initial temperature is 200k. when the temperature is decreased by 67 k, by putting it in a lower temperature freezer, the volume will decrease, according to the ideal gas law. calculate the work for this process. only enter the numeric value as the answer without the unit j the conversion factor between liter atmospheres and joules is 101.3 j = 1 l atm. the gas constant is 0.08206 (l atm)/(mol k). molecular weight of nitrogen is 28 g/mol w =

Answer 1

The work done during the process cannot be computed with the information provided, as we lack specific volumes to apply the formula for isothermal processes work calculation.

Step-by-step explanation:

To calculate the work done when the temperature of a cylinder with a movable piston containing nitrogen is decreased, we must use the formula for work in isothermal processes. Given that the initial temperature is 200 K and it is decreased by 67 K, we can calculate the final temperature (T2 = 200 K - 67 K = 133 K). The work done by the gas during an isothermal process is given by:

W = -nRT ln(V2/V1)

However, we need the number of moles (n), which can be found using the molecular weight of nitrogen (N2) as follows:
n = mass / molar mass = 92 g / 28 g/mol = 3.29 mol

Since the pressure is constant, the ideal gas law allows us to relate the change in volume to the change in temperature directly (V1/T1 = V2/T2). Given that we are not provided with initial volumes, we cannot use this relationship directly. Since this is the case and we do not have enough information to find the specific volumes or to compute the specific work done, the actual numeric value of the work cannot be calculated from the provided information.

Thus, the numeric value of the work done cannot be determined with the details given.