Question

A cell has an emf of 1.50 v and an internal resistance of r = 0.0500 ω. if there is 0.125 a in the cell, what voltage is applied to the external circuit?

Answer 1

The voltage applied to the external circuit can be found using Ohm's Law.

Step-by-step explanation:

The voltage applied to the external circuit can be found using Ohm's Law. Ohm's Law states that the voltage (V) is equal to the current (I) multiplied by the resistance (R).

V = I * R

In this case, the current flowing through the circuit is given as 0.125 A. The resistance of the internal circuit (which includes the cell's internal resistance) can be found using the formula:

R_total = r + R_external

Substituting the given values, we have:

R_total = 0.0500 + R_external

For the given cell, the emf is 1.50 V. The voltage applied to the external circuit is therefore:

V = I * R_external = 0.125 * (1.50 - 0.0500)

V = 0.125 * 1.45 = 0.18125 V

Therefore, the voltage applied to the external circuit is approximately 0.18125 V.