Question

A cliff diver running 3.5 m/s dives out horizontally from the edge of a vertical cliff and reaches the water below 2.0 s late. how far from the base of the cliff does the diver hit the water?

Answer 1

The cliff diver will hit the water 7.0 meters away from the base of the cliff, calculated by multiplying the initial horizontal velocity of 3.5 m/s by the time of 2.0 seconds.

Step-by-step explanation:

The cliff diver's situation is a two-dimensional motion problem in physics, where horizontal and vertical motions are considered separately. The diver starts with a horizontal velocity of 3.5 m/s and no initial vertical velocity since the dive is horizontal. During free fall, the only acceleration acting on them is due to gravity, which is approximately 9.8 m/s2 downward.

To calculate the horizontal distance that the diver travels before hitting the water, use the formula:

Distance = initial velocity × time

which gives us:

Distance = 3.5 m/s × 2.0 s = 7.0 meters

So the diver will hit the water 7.0 meters away from the base of the cliff.