76.9k views
2 votes
dy dt = (1 t)|y| 1 2 y(1) = 1 for each of the following initial value problems state whether or not the existence and uniqueness theoremguarantees that a solution exists.

User Him Hah
by
8.4k points

1 Answer

5 votes

Final answer:

The existence and uniqueness theorem guarantees that a solution exists for this initial value problem.

Step-by-step explanation:

The existence and uniqueness theorem states that for a first-order ordinary differential equation (ODE) y' = f(t,y) with initial condition y(1) = 1, a unique solution exists in a neighborhood of the initial condition if f(t,y) is continuous and satisfies the Lipschitz condition with respect to y.

In this case, we have the ODE dy/dt = (1 - t)|y|^(1/2) with the initial condition y(1) = 1. We can see that the function f(t,y) = (1 - t)|y|^(1/2) is continuous and satisfies the Lipschitz condition with respect to y in a neighborhood of the initial condition. Therefore, the existence and uniqueness theorem guarantees that a solution exists for this initial value problem.

User Mike Meyers
by
7.2k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories