Final answer:
To find the magnitude of the electric field at x = 5.0 m on the x-axis, we can use the formula for the electric field. Using the given information, we calculate the electric field as 36.0 N/C.
Step-by-step explanation:
To find the magnitude of the electric field at the point x = 5.0 m on the x-axis, we can use the formula for the electric field created by a charged rod:
E = k * (total charge)/r^2
In this case, the total charge is the charge per meter multiplied by the length of the rod, and r is the distance from the charge to the point where we are calculating the electric field. Using the given information, we can calculate the electric field at x = 5.0 m.
First, we need to find the length of the rod, which is 3.0 m - (-2.0 m) = 5.0 m. Next, we calculate the total charge: charge per meter * length = 4.0 nC/m * 5.0 m = 20.0 nC.
Finally, we can plug these values into the formula:
E = (9.0 * 10^9 N*m^2/C^2) * (20.0 * 10^-9 C) / (5.0 m)^2
E = 36.0 N/C
Therefore, the magnitude of the electric field at the point x = 5.0 m on the x-axis is 36.0 N/C.