Final answer:
The mass of 41.80 moles of NaBr is 4300.732 grams, calculated by multiplying the moles of NaBr by its molar mass (102.89 g/mol).
Step-by-step explanation:
To calculate the mass in grams of 41.80 moles of NaBr, we'll need to use the molar mass of NaBr, which is the sum of the molar masses of sodium (Na) and bromine (Br). The molar mass of Na is approximately 22.99 g/mol, and the molar mass of Br is approximately 79.90 g/mol. Adding these together gives us a molar mass for NaBr of roughly 22.99 g/mol + 79.90 g/mol = 102.89 g/mol.
Once we have the molar mass, the mass of NaBr can be calculated with the formula: mass = moles × molar mass. So:
mass of NaBr = 41.80 moles × 102.89 g/mol = 4300.732 grams
Therefore, the mass of 41.80 moles of NaBr is 4300.732 grams.