Question

a particle with velocity (-1.1 î 0.3 ĵ ) m/s undergoes a constant acceleration 0.1 î m/s2 for 5 seconds. what is the particle's speed at the end of this time? answer in m/s.

Answer 1

The particle's speed at the end of 5 seconds is 6.05 m/s.

Step-by-step explanation:

To find the particle's speed at the end of 5 seconds, we first need to find its final velocity. The particle undergoes a constant acceleration of 0.1 î m/s² for 5 seconds. We can use the formula v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.

Given u = -1.1 î 0.3 ĵ m/s and a = 0.1 î m/s², we can plug these values into the formula to find the final velocity:

v = (-1.1 î 0.3 ĵ) + (0.1 î m/s²)(5 s)

Now, we can perform the vector addition and calculate the magnitude of the final velocity:

|v| = sqrt((-1.1 + 0.1 * 5)^2 + (0.3)^2)

|v| = sqrt((-1.1 * 5.5)^2 + (0.3)^2)

|v| = sqrt(6.05^2 + 0.09)

|v| = sqrt(36.61 + 0.09)

|v| = sqrt(36.7)

|v| = 6.05 m/s