Final answer:
The initial acceleration of a proton in a 5.00 × 10^6 N/C electric field can be calculated using Newton's second law of motion.
Step-by-step explanation:
The initial acceleration of a proton in a 5.00 × 106 N/C electric field can be calculated using Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration. In this case, the force acting on the proton is the electric force, given by the formula:
F = qE
where F is the force, q is the charge of the proton (1.6 x 10-19 C), and E is the electric field strength (5.00 × 106 N/C).
Using this formula, we can find the acceleration:
a = F/m
where m is the mass of the proton (1.67 x 10-27 kg).
a = (1.6 x 10-19 C * 5.00 × 106 N/C) / (1.67 x 10-27 kg)