Final answer:
To have $10,000 in ten years with a 10% interest rate compounded annually, you would need to deposit approximately $3,854.00
Step-by-step explanation:
To find out how much money you need to deposit into a bank account earning 10% interest compounded annually to have $10,000 in ten years, you can use the formula for compound interest:
A = P(1 + r/n)^(nt)
Where:
- A is the final amount (which is $10,000)
- P is the principal amount (which is what we need to find)
- r is the annual interest rate (which is 10% or 0.10)
- n is the number of times the interest is compounded per year (which is 1, since it's compounded annually)
- t is the number of years (which is 10)
Plugging these values into the formula:
$10,000 = P(1 + 0.10/1)^(1*10)
$10,000 = P(1 + 0.10)^10
$10,000 = P(1.1)^10
To isolate P, divide both sides of the equation by (1.1)^10:
P = $10,000 / (1.1)^10
Using a calculator, the value of P comes out to be approximately $3,854.00 (rounded to the nearest cent).