Final answer:
The standard entropy change (ΔS°) for the reaction C2H2(g) + 2 H2(g) → C2H6(g) is calculated using the standard molar entropies of the reactants and products. The ΔS° is -102.4 J/mol·K.
Step-by-step explanation:
The student has asked to calculate the standard entropy change (ΔS°) for a chemical reaction using the provided standard molar entropies (S°) of reactants and products. To calculate ΔS°, we use the formula:
ΔS° = ΣS°(products) - ΣS°(reactants)
For the reaction C2H2(g) + 2 H2 (g) → C2H6(g), the S° values are:
- S° for C2H2(g) = 200.9 J/mol·K
- S° for 2H2 = 130.7 J/mol·K (for two moles)
- S° for C2H6 = 229.2 J/mol·K
Substituting these values into the formula gives:
ΔS° = (229.2) - (200.9 + 130.7)
ΔS° = 229.2 - 331.6 = -102.4 J/mol·K
Therefore, the standard entropy change for the reaction is -102.4 J/mol·K.