Final answer:
To find the volume of the solid generated by revolving the region bounded by y = 3 √sinx, y = 0, and x1 = π/4, and x2 = 3π/4 about the x-axis, you can use the method of cylindrical shells.
Step-by-step explanation:
To find the volume of the solid generated by revolving the region bounded by y = 3 √sinx, y = 0, and x1 = π/4, and x2 = 3π/4 about the x-axis, we can use the method of cylindrical shells.
The volume of the solid is given by the integral of the circumference of each shell multiplied by its height. In this case, the circumference of each shell is given by 2πx and the height is given by 3 √sinx.
So the volume is V = ∫(2πx)(3 √sinx) dx with limits x1 to x2.