Final answer:
The particular solution for the differential equation is y_p(t) = t⁶e⁴ᵗ.
Step-by-step explanation:
The given differential equation is y"-8y'+ 16y=20t⁶e⁴ᵗ. To find the particular solution using the Method of Undetermined Coefficients, we assume a particular solution of the form:
y_p(t) = At⁶e⁴ᵗ
We substitute the assumed solution into the differential equation and equate coefficients:
(20A)e⁴ᵗ = 20t⁶e⁴ᵗ
By comparing the powers of t and the exponential terms, we find A = 1.
Therefore, the particular solution is y_p(t) = t⁶e⁴ᵗ.