Final answer:
A heat engine with an efficiency of 0.37 that absorbs 400 J of heat per cycle performs 148 J of work and rejects 252 J of heat per cycle.
Step-by-step explanation:
The student has inquired about the amount of work performed per cycle and the amount of heat rejected per cycle by a heat engine with a given efficiency.
Part A: Work Performed per Cycle
To calculate the work done by the heat engine per cycle, we use the formula:
Work done (W) = Efficiency (η) × Heat absorbed (Qin)
Given the efficiency of 0.37 and heat absorption of 400 J per cycle, the work done is:
W = 0.37 × 400 J = 148 J
Part B: Heat Rejected per Cycle
To calculate the heat rejected, we use the conservation of energy:
Heat rejected (Qout) = Heat absorbed (Qin) - Work done (W)
Qout = 400 J - 148 J = 252 J
Therefore, the heat engine performs 148 J of work and rejects 252 J of heat per cycle.