Final answer:
The confidence interval at a critical value of 2.88 corresponds to a 99.6% confidence level, and at 1.41, it's approximately 84.1%. For a 99.7% confidence level, the z-score is about 3.00, and for a 78% confidence level, it's approximately 1.23.
Step-by-step explanation:
The answers to the questions regarding confidence intervals for a normal population distribution are:
- (a) To find the confidence level for the interval x ± 2.88√÷ n, we need to determine the z-score that corresponds to this critical value. Using a standard normal distribution table or calculator, we find that a z-score of 2.88 corresponds to a confidence level of approximately 99.6%. Therefore, the confidence level is 99.6% (rounded to one decimal place).
- (b) Similarly, a z-score of 1.41 corresponds to a confidence level of approximately 84.1%. So, the confidence level is 84.1% (rounded to one decimal place).
- (c) For a confidence level of 99.7%, we are looking for the z-score that corresponds to the middle 99.7% of the distribution, leaving 0.3% in the tails. The two tails would each contain 0.15%, and the corresponding z-score is approximately 3.00. Thus, z√÷ = 3.00 (rounded to two decimal places).
- (d) For a confidence level of 78%, we are looking for a z-score that corresponds to the middle 78% of the distribution, leaving 22% in the tails. The two tails would each contain 11%, and the corresponding z-score is approximately 1.23. Thus, z√÷ = 1.23 (rounded to two decimal places).