Question

If acceleration due to gravity on the earth is g, which formula gives the acceleration due to gravity on Loput?

a.g1.7 /5.6
b.g1.7² / 5.6
c.g1.7² /5.6²
d.g5.6/ 1.7
e.g5.6²/ 1.7²
f.g5.6/ 1.7²

Answer 1

The formula that gives the acceleration due to gravity on Loput is g5.6/1.7² (option e).

Step-by-step explanation:

The formula that gives the acceleration due to gravity on Loput is g5.6/1.7² (option e).

To understand why this is the correct formula, we need to know that the acceleration due to gravity is given by the formula g = GM/r², where G is the gravitational constant, M is the mass of the celestial body, and r is the distance from the center of the celestial body.

In this case, we are comparing the acceleration due to gravity on Earth (g) with the acceleration due to gravity on Loput. Let's call the acceleration due to gravity on Loput as g1.

Using the formula for Earth's acceleration due to gravity (g = GM/r²), we can write it as:

g = GM/r²

g1 = GM1/r1²

Dividing the two equations, we get:

g1/g = (GM1/r1²)/(GM/r²)

Simplifying it, we have:

g1/g = M1/M (r/r1)²

M1/M = g1/g * (r/r1)²

Now, we can express M1 (mass of Loput) in terms of M (mass of Earth):

M1 = M * (g1/g) * (r/r1)²

Since we want to find the acceleration due to gravity on Loput (g1), we can rearrange the equation as:

g1 = g * (M1/M) * (r1/r)²

Comparing this equation with the given options, we can see that the correct formula is g5.6/1.7² (option e).