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What is the strength of the electric field between two parallel conducting plates separated by 1.00 cm and having a potential difference (voltage) between them of 1.50×10⁴ V

User Lei Li
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Final answer:

The strength of the electric field between two parallel conducting plates can be calculated using the equation: Electric field strength (E) = Voltage (V) / Distance (d). In this case, the electric field strength is 1.50×10⁶ V/m.

Step-by-step explanation:

The strength of the electric field between two parallel conducting plates can be calculated using the equation:

Electric field strength (E) = Voltage (V) / Distance (d)

In this case, the voltage between the plates is given as 1.50×10⁴ V and the distance between the plates is 1.00 cm (which is equal to 0.01 m). Substituting these values into the equation, we get:

E = 1.50×10⁴ V / 0.01 m = 1.50×10⁶ V/m

Therefore, the electric field strength between the parallel conducting plates is 1.50×10⁶ V/m.

User Ali Alizadeh
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