Final answer:
Using the kinematic equation for vertical motion, a ball thrown upward with an initial speed of 23.5 m/s will reach a maximum height of 28.09 meters.
Step-by-step explanation:
Calculating Maximum Height of a Thrown Ball
To determine the maximum height that a ball will reach when thrown straight up with an initial speed of 23.5 meters per second (m/s), we can use the kinematic equation for motion under constant acceleration due to gravity. The equation is:
h = (v^2) / (2g)
where h is the maximum height, v is the initial velocity, and g is the acceleration due to gravity (approximately 9.81 m/s^2). Plugging in the numbers:
h = (23.5^2) / (2 * 9.81) = 28.09 meters
Thus, the maximum height reached by the ball would be 28.09 meters.