Question

A 541 g ball strikes a wall at 14.2 m/s and rebounds at 11.3 m/s. the ball is in contact with the wall for 0.032 s. what is the magnitude of the average force acting on the ball during the collision? answer in units of n.

Answer 1

The magnitude of the average force acting on the ball during the collision is approximately 48.72 N.

Step-by-step explanation:

To calculate the magnitude of the average force acting on the ball during the collision, we can use the equation:

Force = (Change in momentum) / (Change in time)

The change in momentum can be calculated using the initial and final velocities of the ball, as well as its mass:

Change in momentum = (mass * final velocity) - (mass * initial velocity)

Substituting the given values:

Change in momentum = (0.541 kg * 11.3 m/s) - (0.541 kg * 14.2 m/s)

Change in momentum = -0.541 kg * 2.9 m/s

Finally, we can substitute the change in momentum and the time of contact into the equation for force:

Force = (-0.541 kg * 2.9 m/s) / 0.032 s

Using a calculator, the magnitude of the average force is approximately 48.72 N.